Distance from Sihanoukville to Tucupita
Distance from Sihanoukville to Tucupita is 17,317 kilometers. This air travel distance is equal to 10,760 miles.
The air travel (bird fly) shortest distance between Sihanoukville and Tucupita is 17,317 km or 10,760 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sihanoukville to Tucupita, It takes 19.21 hours to arrive.
Sihanoukville
Sihanoukville is located in Cambodia.
| GPS Coordinates (DMS) | 10° 36´ 33.5520'' N 103° 31´ 46.4880'' E |
|---|---|
| Latitude | 10.60932 |
| Longitude | 103.52958 |
| Altitude | 6 m |
| Country | Cambodia |
Sihanoukville Distances to Cities
| Sihanoukville | Distance |
|---|---|
| Distance from Sihanoukville to San Juan De Los Morros | 17,526 km |
| Distance from Sihanoukville to Tucupita | 17,317 km |