Distance from Sihanoukville to San Juan de los Morros
Distance from Sihanoukville to San Juan de los Morros is 17,526 kilometers. This air travel distance is equal to 10,890 miles.
The air travel (bird fly) shortest distance between Sihanoukville and San Juan de los Morros is 17,526 km or 10,890 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sihanoukville to San Juan de los Morros, It takes 19.45 hours to arrive.
Sihanoukville
Sihanoukville is located in Cambodia.
| GPS Coordinates (DMS) | 10° 36´ 33.5520'' N 103° 31´ 46.4880'' E |
|---|---|
| Latitude | 10.60932 |
| Longitude | 103.52958 |
| Altitude | 6 m |
| Country | Cambodia |
Sihanoukville Distances to Cities
| Sihanoukville | Distance |
|---|---|
| Distance from Sihanoukville to San Juan De Los Morros | 17,526 km |
| Distance from Sihanoukville to Tucupita | 17,317 km |
San Juan de los Morros
San Juan de los Morros is located in Venezuela.
| GPS Coordinates | 9° 54´ 41.4720'' N 67° 21´ 13.7160'' W |
|---|---|
| Latitude | 9.91152 |
| Longitude | -67.35381 |
| Altitude | 433 m |
| Country | Venezuela |