Distance from Humacao to Sevastopol
Distance from Humacao to Sevastopol is 9,327 kilometers. This air travel distance is equal to 5,796 miles.
The air travel (bird fly) shortest distance between Humacao and Sevastopol is 9,327 km= 5,796 miles.
If you travel with an airplane (which has average speed of 560 miles) from Humacao to Sevastopol, It takes 10.35 hours to arrive.
Humacao
Humacao is located in Puerto Rico.
| GPS Coordinates (DMS) | 18° 8´ 58.8480'' N 65° 49´ 38.5680'' W |
|---|---|
| Latitude | 18.14968 |
| Longitude | -65.82738 |
| Altitude | 22 m |
| Country | Puerto Rico |
Humacao Distances to Cities
| Humacao | Distance |
|---|---|
| Distance from Humacao to Sevastopol | 9,327 km |
Sevastopol
Sevastopol is located in Ukraine.
| GPS Coordinates | 44° 35´ 19.7880'' N 33° 31´ 20.6400'' E |
|---|---|
| Latitude | 44.58883 |
| Longitude | 33.52240 |
| Altitude | 72 m |
| Country | Ukraine |