Distance from Zhangjiagang to Vernon Hills
Distance from Zhangjiagang to Vernon Hills is 11,300 kilometers. This air travel distance is equal to 7,021 miles.
The air travel (bird fly) shortest distance between Zhangjiagang and Vernon Hills is 11,300 km or 7,021 miles.
If you travel with an airplane (which has average speed of 560 miles) from Zhangjiagang to Vernon Hills, It takes 12.54 hours to arrive.
Zhangjiagang
Zhangjiagang is located in China.
| GPS Coordinates (DMS) | 31° 51´ 54.0000'' N 120° 32´ 20.0040'' E |
|---|---|
| Latitude | 31.86500 |
| Longitude | 120.53889 |
| Altitude | 13 m |
| Country | China |
Zhangjiagang Distances to Cities
| Zhangjiagang | Distance |
|---|---|
| Distance from Zhangjiagang to Vernon Hills | 11,300 km |
| Distance from Zhangjiagang to Skokie | 11,327 km |
| Distance from Zhangjiagang to Pine Hills | 12,926 km |
| Distance from Zhangjiagang to Laguna Beach | 10,539 km |
| Distance from Zhangjiagang to Ansonia | 11,779 km |
Vernon Hills
Vernon Hills is located in United States.
| GPS Coordinates | 42° 13´ 10.0920'' N 87° 58´ 46.2720'' W |
|---|---|
| Latitude | 42.21947 |
| Longitude | -87.97952 |
| Altitude | 226 m |
| Country | United States |