Distance from Yaracuy to Seminole
Distance from Yaracuy to Seminole is 2,427 kilometers. This air travel distance is equal to 1,508 miles.
The air travel (bird fly) shortest distance between Yaracuy and Seminole is 2,427 km or 1,508 miles.
If you travel with an airplane (which has average speed of 560 miles) from Yaracuy to Seminole, It takes 2.69 hours to arrive.
Yaracuy
Yaracuy is located in Venezuela.
| GPS Coordinates (DMS) | 10° 25´ 3.5040'' N 68° 42´ 55.8000'' W |
|---|---|
| Latitude | 10.41764 |
| Longitude | -68.71550 |
| Altitude | 408 m |
| Country | Venezuela |
Yaracuy Distances to Cities
| Yaracuy | Distance |
|---|---|
| Distance from Yaracuy to Mineola | 3,395 km |
| Distance from Yaracuy to Seminole | 2,427 km |
| Distance from Yaracuy to Saugus | 3,558 km |
| Distance from Yaracuy to Frisco | 3,821 km |
| Distance from Yaracuy to Keene | 3,620 km |
Seminole
Seminole is located in United States.
| GPS Coordinates | 27° 50´ 23.1000'' N 82° 47´ 28.3560'' W |
|---|---|
| Latitude | 27.83975 |
| Longitude | -82.79121 |
| Altitude | 16 m |
| Country | United States |