Distance from Waukegan to San Jose de Guanipa
Distance from Waukegan to San José de Guanipa is 4,373 kilometers. This air travel distance is equal to 2,717 miles.
The air travel (bird fly) shortest distance between Waukegan and San José de Guanipa is 4,373 km= 2,717 miles.
If you travel with an airplane (which has average speed of 560 miles) from Waukegan to San Jose de Guanipa, It takes 4.85 hours to arrive.
Waukegan
Waukegan is located in United States.
| GPS Coordinates (DMS) | 42° 21´ 49.0680'' N 87° 50´ 41.2440'' W |
|---|---|
| Latitude | 42.36363 |
| Longitude | -87.84479 |
| Altitude | 199 m |
| Country | United States |
Waukegan Distances to Cities
| Waukegan | Distance |
|---|---|
| Distance from Waukegan to San Jose De Guanipa | 4,373 km |
| Distance from Waukegan to Cabimas | 3,887 km |
San Jose de Guanipa
San Jose de Guanipa is located in Venezuela.
| GPS Coordinates | 8° 53´ 14.0640'' N 64° 9´ 54.4320'' W |
|---|---|
| Latitude | 8.88724 |
| Longitude | -64.16512 |
| Altitude | 261 m |
| Country | Venezuela |