Distance from Wakayama-shi to Drobeta-Turnu Severin
Distance from Wakayama-shi to Drobeta-Turnu Severin is 8,941 kilometers. This air travel distance is equal to 5,556 miles.
The air travel (bird fly) shortest distance between Wakayama-shi and Drobeta-Turnu Severin is 8,941 km or 5,556 miles.
If you travel with an airplane (which has average speed of 560 miles) from Wakayama-shi to Drobeta-Turnu Severin, It takes 9.92 hours to arrive.
Wakayama-shi
Wakayama-shi is located in Japan.
| GPS Coordinates (DMS) | 34° 13´ 33.9960'' N 135° 10´ 3.0000'' E | 
|---|---|
| Latitude | 34.22611 | 
| Longitude | 135.16750 | 
| Altitude | 18 m | 
| Country | Japan | 
Wakayama-shi Distances to Cities
| Wakayama-shi | Distance | 
|---|---|
| Distance from Wakayama Shi to Drobeta Turnu Severin | 8,941 km | 
Drobeta-Turnu Severin
Drobeta-Turnu Severin is located in Romania.
| GPS Coordinates | 44° 37´ 54.9840'' N 22° 39´ 21.9960'' E | 
|---|---|
| Latitude | 44.63194 | 
| Longitude | 22.65611 | 
| Altitude | 86 m | 
| Country | Romania | 
