Distance from Wakayama-shi to Drobeta-Turnu Severin
Distance from Wakayama-shi to Drobeta-Turnu Severin is 8,941 kilometers. This air travel distance is equal to 5,556 miles.
The air travel (bird fly) shortest distance between Wakayama-shi and Drobeta-Turnu Severin is 8,941 km= 5,556 miles.
If you travel with an airplane (which has average speed of 560 miles) from Wakayama-shi to Drobeta-Turnu Severin, It takes 9.92 hours to arrive.
Wakayama-shi
Wakayama-shi is located in Japan.
| GPS Coordinates (DMS) | 34° 13´ 33.9960'' N 135° 10´ 3.0000'' E |
|---|---|
| Latitude | 34.22611 |
| Longitude | 135.16750 |
| Altitude | 18 m |
| Country | Japan |
Wakayama-shi Distances to Cities
| Wakayama-shi | Distance |
|---|---|
| Distance from Wakayama Shi to Drobeta Turnu Severin | 8,941 km |
Drobeta-Turnu Severin
Drobeta-Turnu Severin is located in Romania.
| GPS Coordinates | 44° 37´ 54.9840'' N 22° 39´ 21.9960'' E |
|---|---|
| Latitude | 44.63194 |
| Longitude | 22.65611 |
| Altitude | 86 m |
| Country | Romania |