Distance from Viterbo to Peekskill
Distance from Viterbo to Peekskill is 6,810 kilometers. This air travel distance is equal to 4,232 miles.
The air travel (bird fly) shortest distance between Viterbo and Peekskill is 6,810 km or 4,232 miles.
If you travel with an airplane (which has average speed of 560 miles) from Viterbo to Peekskill, It takes 7.56 hours to arrive.
Viterbo
Viterbo is located in Italy.
| GPS Coordinates (DMS) | 42° 25´ 23.5920'' N 12° 6´ 41.0760'' E |
|---|---|
| Latitude | 42.42322 |
| Longitude | 12.11141 |
| Altitude | 358 m |
| Country | Italy |
Viterbo Distances to Cities
| Viterbo | Distance |
|---|---|
| Distance from Viterbo to Los Angeles | 10,147 km |
| Distance from Viterbo to Peekskill | 6,810 km |
| Distance from Viterbo to Lenexa | 8,367 km |
| Distance from Viterbo to Dekalb | 7,768 km |
| Distance from Viterbo to Brook Park | 7,347 km |
Peekskill
Peekskill is located in United States.
| GPS Coordinates | 41° 17´ 24.3240'' N 73° 55´ 13.5120'' W |
|---|---|
| Latitude | 41.29009 |
| Longitude | -73.92042 |
| Altitude | 49 m |
| Country | United States |