Distance from Vinnyts'ka to Huaquillas
Distance from Vinnyts'ka to Huaquillas is 11,653 kilometers. This air travel distance is equal to 7,241 miles.
The air travel (bird fly) shortest distance between Vinnyts'ka and Huaquillas is 11,653 km or 7,241 miles.
If you travel with an airplane (which has average speed of 560 miles) from Vinnyts'ka to Huaquillas, It takes 12.93 hours to arrive.
Vinnyts'ka
Vinnyts'ka is located in Ukraine.
| GPS Coordinates (DMS) | 49° 13´ 59.0880'' N 28° 28´ 5.5920'' E |
|---|---|
| Latitude | 49.23308 |
| Longitude | 28.46822 |
| Altitude | 264 m |
| Country | Ukraine |
Vinnyts'ka Distances to Cities
| Vinnyts'ka | Distance |
|---|---|
| Distance from Vinnyts Ka to Guaranda | 11,405 km |
| Distance from Vinnyts Ka to Bahia De Caraquez | 11,421 km |
| Distance from Vinnyts Ka to Huaquillas | 11,653 km |
| Distance from Vinnyts Ka to Portoviejo | 11,462 km |
Huaquillas
Huaquillas is located in Ecuador.
| GPS Coordinates | 3° 28´ 30.8280'' S 80° 13´ 51.0240'' W |
|---|---|
| Latitude | -3.47523 |
| Longitude | -80.23084 |
| Altitude | 9 m |
| Country | Ecuador |