Distance from Tungurahua to San Giuseppe Vesuviano
Distance from Tungurahua to San Giuseppe Vesuviano is 10,362 kilometers. This air travel distance is equal to 6,439 miles.
The air travel (bird fly) shortest distance between Tungurahua and San Giuseppe Vesuviano is 10,362 km or 6,439 miles.
If you travel with an airplane (which has average speed of 560 miles) from Tungurahua to San Giuseppe Vesuviano, It takes 11.5 hours to arrive.
Tungurahua
Tungurahua is located in Ecuador.
| GPS Coordinates (DMS) | 1° 15´ 48.7080'' S 78° 33´ 57.9240'' W |
|---|---|
| Latitude | -1.26353 |
| Longitude | -78.56609 |
| Altitude | 2602 m |
| Country | Ecuador |
Tungurahua Distances to Cities
| Tungurahua | Distance |
|---|---|
| Distance from Tungurahua to Asti | 9,854 km |
| Distance from Tungurahua to Lido | 10,183 km |
| Distance from Tungurahua to Caltanissetta | 10,329 km |
| Distance from Tungurahua to Comiso | 10,379 km |
| Distance from Tungurahua to San Giuseppe Vesuviano | 10,362 km |
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
| GPS Coordinates | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
|---|---|
| Latitude | 40.83034 |
| Longitude | 14.50342 |
| Altitude | 106 m |
| Country | Italy |