Distance from Sitarganj to Pinewood
Distance from Sitārganj to Pinewood is 13,575 kilometers. This air travel distance is equal to 8,435 miles.
The air travel (bird fly) shortest distance between Sitārganj and Pinewood is 13,575 km or 8,435 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sitarganj to Pinewood, It takes 15.06 hours to arrive.
Sitarganj
Sitarganj is located in India.
| GPS Coordinates (DMS) | 28° 55´ 55.7040'' N 79° 42´ 16.2720'' E |
|---|---|
| Latitude | 28.93214 |
| Longitude | 79.70452 |
| Altitude | 217 m |
| Country | India |
Sitārganj Distances to Cities
| Sitārganj | Distance |
|---|---|
| Distance from Sitarganj to Holden | 11,593 km |
| Distance from Sitarganj to Pinewood | 13,575 km |
| Distance from Sitarganj to Scottsdale | 12,986 km |
| Distance from Sitarganj to Fond Du Lac | 11,864 km |
| Distance from Sitarganj to San Francisco | 12,270 km |
Pinewood
Pinewood is located in United States.
| GPS Coordinates | 25° 52´ 8.3280'' N 80° 13´ 1.1640'' W |
|---|---|
| Latitude | 25.86898 |
| Longitude | -80.21699 |
| Altitude | 10 m |
| Country | United States |