Distance from Sitapur to Oakley
Distance from Sītāpur to Oakley is 12,383 kilometers. This air travel distance is equal to 7,694 miles.
The air travel (bird fly) shortest distance between Sītāpur and Oakley is 12,383 km or 7,694 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sitapur to Oakley, It takes 13.74 hours to arrive.
Sitapur
Sitapur is located in India.
| GPS Coordinates (DMS) | 27° 33´ 42.9120'' N 80° 40´ 57.5400'' E |
|---|---|
| Latitude | 27.56192 |
| Longitude | 80.68265 |
| Altitude | 143 m |
| Country | India |
Sītāpur Distances to Cities
| Sītāpur | Distance |
|---|---|
| Distance from Sitapur to Laramie | 12,352 km |
| Distance from Sitapur to Corsicana | 13,395 km |
| Distance from Sitapur to Neenah | 11,983 km |
| Distance from Sitapur to Oakley | 12,383 km |
| Distance from Sitapur to Marshall | 13,331 km |
Oakley
Oakley is located in United States.
| GPS Coordinates | 37° 59´ 50.7120'' N 121° 42´ 44.8200'' W |
|---|---|
| Latitude | 37.99742 |
| Longitude | -121.71245 |
| Altitude | 5 m |
| Country | United States |