Distance from Sihanoukville to Philipsburg
Distance from Sihanoukville to Philipsburg is 16,516 kilometers. This air travel distance is equal to 10,263 miles.
The air travel (bird fly) shortest distance between Sihanoukville and Philipsburg is 16,516 km or 10,263 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sihanoukville to Philipsburg, It takes 18.33 hours to arrive.
Sihanoukville
Sihanoukville is located in Cambodia.
| GPS Coordinates (DMS) | 10° 36´ 33.5520'' N 103° 31´ 46.4880'' E |
|---|---|
| Latitude | 10.60932 |
| Longitude | 103.52958 |
| Altitude | 6 m |
| Country | Cambodia |
Sihanoukville Distances to Cities
| Sihanoukville | Distance |
|---|---|
| Distance from Sihanoukville to Philipsburg | 16,516 km |
Philipsburg
Philipsburg is located in Sint Maarten.
| GPS Coordinates | 18° 1´ 33.6000'' N 63° 2´ 44.9520'' W |
|---|---|
| Latitude | 18.02600 |
| Longitude | -63.04582 |
| Altitude | 0 m |
| Country | Sint Maarten |