Distance from Siguatepeque to Palm Harbor
Distance from Siguatepeque to Palm Harbor is 1,582 kilometers. This air travel distance is equal to 983 miles.
The air travel (bird fly) shortest distance between Siguatepeque and Palm Harbor is 1,582 km= 983 miles.
If you travel with an airplane (which has average speed of 560 miles) from Siguatepeque to Palm Harbor, It takes 1.76 hours to arrive.
Siguatepeque
Siguatepeque is located in Honduras.
| GPS Coordinates (DMS) | 14° 35´ 60.0000'' N 87° 49´ 59.9880'' W |
|---|---|
| Latitude | 14.60000 |
| Longitude | -87.83333 |
| Altitude | 1079 m |
| Country | Honduras |
Siguatepeque Distances to Cities
| Siguatepeque | Distance |
|---|---|
| Distance from Siguatepeque to San Pablo | 4,269 km |
| Distance from Siguatepeque to Greeneville | 2,440 km |
| Distance from Siguatepeque to Montgomery Village | 2,916 km |
| Distance from Siguatepeque to Pomona | 3,699 km |
| Distance from Siguatepeque to Palm Harbor | 1,582 km |
Palm Harbor
Palm Harbor is located in United States.
| GPS Coordinates | 28° 4´ 41.0520'' N 82° 45´ 49.3560'' W |
|---|---|
| Latitude | 28.07807 |
| Longitude | -82.76371 |
| Altitude | 20 m |
| Country | United States |