Distance from Saramacca to Minot
Distance from Saramacca to Minot is 6,383 kilometers. This air travel distance is equal to 3,966 miles.
The air travel (bird fly) shortest distance between Saramacca and Minot is 6,383 km= 3,966 miles.
If you travel with an airplane (which has average speed of 560 miles) from Saramacca to Minot, It takes 7.08 hours to arrive.
Saramacca
Saramacca is located in Suriname.
| GPS Coordinates (DMS) | 5° 43´ 26.6880'' N 55° 40´ 8.2560'' W |
|---|---|
| Latitude | 5.72408 |
| Longitude | -55.66896 |
| Altitude | 4 m |
| Country | Suriname |
Saramacca Distances to Cities
| Saramacca | Distance |
|---|---|
| Distance from Saramacca to University Place | 7,808 km |
| Distance from Saramacca to Desoto | 5,201 km |
| Distance from Saramacca to Ramona | 6,992 km |
| Distance from Saramacca to Arlington Heights | 5,140 km |
| Distance from Saramacca to Minot | 6,383 km |
Minot
Minot is located in United States.
| GPS Coordinates | 48° 13´ 57.0360'' N 101° 17´ 46.5720'' W |
|---|---|
| Latitude | 48.23251 |
| Longitude | -101.29627 |
| Altitude | 491 m |
| Country | United States |