Distance from Saramacca to Arlington Heights
Distance from Saramacca to Arlington Heights is 5,140 kilometers. This air travel distance is equal to 3,194 miles.
The air travel (bird fly) shortest distance between Saramacca and Arlington Heights is 5,140 km= 3,194 miles.
If you travel with an airplane (which has average speed of 560 miles) from Saramacca to Arlington Heights, It takes 5.7 hours to arrive.
Saramacca
Saramacca is located in Suriname.
| GPS Coordinates (DMS) | 5° 43´ 26.6880'' N 55° 40´ 8.2560'' W |
|---|---|
| Latitude | 5.72408 |
| Longitude | -55.66896 |
| Altitude | 4 m |
| Country | Suriname |
Saramacca Distances to Cities
| Saramacca | Distance |
|---|---|
| Distance from Saramacca to University Place | 7,808 km |
| Distance from Saramacca to Desoto | 5,201 km |
| Distance from Saramacca to Ramona | 6,992 km |
| Distance from Saramacca to Arlington Heights | 5,140 km |
| Distance from Saramacca to Minot | 6,383 km |
Arlington Heights
Arlington Heights is located in United States.
| GPS Coordinates | 42° 5´ 18.0960'' N 87° 58´ 50.2680'' W |
|---|---|
| Latitude | 42.08836 |
| Longitude | -87.98063 |
| Altitude | 219 m |
| Country | United States |