Distance from San Antonio de los Banos to Lake Worth
Distance from San Antonio de los Baños to Lake Worth is 481 kilometers. This air travel distance is equal to 299 miles.
The air travel (bird fly) shortest distance between San Antonio de los Baños and Lake Worth is 481 km or 299 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Antonio de los Banos to Lake Worth, It takes 0.53 hours to arrive.
San Antonio de los Banos
San Antonio de los Banos is located in Cuba.
| GPS Coordinates (DMS) | 22° 53´ 27.9960'' N 82° 29´ 57.0120'' W |
|---|---|
| Latitude | 22.89111 |
| Longitude | -82.49917 |
| Altitude | 62 m |
| Country | Cuba |
San Antonio de los Baños Distances to Cities
Lake Worth
Lake Worth is located in United States.
| GPS Coordinates | 26° 36´ 57.2400'' N 80° 3´ 25.1640'' W |
|---|---|
| Latitude | 26.61590 |
| Longitude | -80.05699 |
| Altitude | 13 m |
| Country | United States |