Distance from Salvaleon de Higuey to Austin
Distance from Salvaleón de Higüey to Austin is 3,202 kilometers. This air travel distance is equal to 1,990 miles.
The air travel (bird fly) shortest distance between Salvaleón de Higüey and Austin is 3,202 km or 1,990 miles.
If you travel with an airplane (which has average speed of 560 miles) from Salvaleon de Higuey to Austin, It takes 3.55 hours to arrive.
Salvaleon de Higuey
Salvaleon de Higuey is located in Dominican Republic.
| GPS Coordinates (DMS) | 18° 36´ 54.0360'' N 68° 42´ 28.7280'' W |
|---|---|
| Latitude | 18.61501 |
| Longitude | -68.70798 |
| Altitude | 95 m |
| Country | Dominican Republic |
Salvaleón de Higüey Distances to Cities
| Salvaleón de Higüey | Distance |
|---|---|
| Distance from Salvaleon De Higuey to Albany Ny | 2,707 km |
| Distance from Salvaleon De Higuey to Austin Tx | 3,202 km |
| Distance from Salvaleon De Higuey to Honolulu | 9,196 km |
Austin
Austin is located in United States.
| GPS Coordinates | 30° 16´ 1.7400'' N 97° 44´ 35.0160'' W |
|---|---|
| Latitude | 30.26715 |
| Longitude | -97.74306 |
| Altitude | 165 m |
| Country | United States |