Distance from Sagua de Tanamo to Port-de-Paix
Distance from Sagua de Tánamo to Port-de-Paix is 262 kilometers. This air travel distance is equal to 163 miles.
The air travel (bird fly) shortest distance between Sagua de Tánamo and Port-de-Paix is 262 km or 163 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sagua de Tanamo to Port-de-Paix, It takes 0.29 hours to arrive.
Sagua de Tanamo
Sagua de Tanamo is located in Cuba.
| GPS Coordinates (DMS) | 20° 34´ 54.9840'' N 75° 14´ 29.0040'' W |
|---|---|
| Latitude | 20.58194 |
| Longitude | -75.24139 |
| Altitude | 27 m |
| Country | Cuba |
Sagua de Tánamo Distances to Cities
Port-de-Paix
Port-de-Paix is located in Haiti.
| GPS Coordinates | 19° 56´ 20.0400'' N 72° 49´ 57.2520'' W |
|---|---|
| Latitude | 19.93890 |
| Longitude | -72.83257 |
| Altitude | 10 m |
| Country | Haiti |