Distance from Sagua de Tanamo to Jarabacoa
Distance from Sagua de Tánamo to Jarabacoa is 509 kilometers. This air travel distance is equal to 316 miles.
The air travel (bird fly) shortest distance between Sagua de Tánamo and Jarabacoa is 509 km= 316 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sagua de Tanamo to Jarabacoa, It takes 0.56 hours to arrive.
Sagua de Tanamo
Sagua de Tanamo is located in Cuba.
| GPS Coordinates (DMS) | 20° 34´ 54.9840'' N 75° 14´ 29.0040'' W |
|---|---|
| Latitude | 20.58194 |
| Longitude | -75.24139 |
| Altitude | 27 m |
| Country | Cuba |
Sagua de Tánamo Distances to Cities
Jarabacoa
Jarabacoa is located in Dominican Republic.
| GPS Coordinates | 19° 7´ 0.5880'' N 70° 38´ 9.4200'' W |
|---|---|
| Latitude | 19.11683 |
| Longitude | -70.63595 |
| Altitude | 535 m |
| Country | Dominican Republic |