Distance from Puerto de la Cruz to Oakley
Distance from Puerto de la Cruz to Oakley is 9,313 kilometers. This air travel distance is equal to 5,787 miles.
The air travel (bird fly) shortest distance between Puerto de la Cruz and Oakley is 9,313 km or 5,787 miles.
If you travel with an airplane (which has average speed of 560 miles) from Puerto de la Cruz to Oakley, It takes 10.33 hours to arrive.
Puerto de la Cruz
Puerto de la Cruz is located in Spain.
| GPS Coordinates (DMS) | 28° 24´ 50.2920'' N 16° 32´ 55.2120'' W |
|---|---|
| Latitude | 28.41397 |
| Longitude | -16.54867 |
| Altitude | 43 m |
| Country | Spain |
Puerto de la Cruz Distances to Cities
| Puerto de la Cruz | Distance |
|---|---|
| Distance from Puerto De La Cruz to Franklin Park | 6,480 km |
| Distance from Puerto De La Cruz to Vernon Hills | 6,483 km |
| Distance from Puerto De La Cruz to Oakley | 9,313 km |
| Distance from Puerto De La Cruz to Sugar Land | 7,539 km |
| Distance from Puerto De La Cruz to Monterey Park | 9,257 km |
Oakley
Oakley is located in United States.
| GPS Coordinates | 37° 59´ 50.7120'' N 121° 42´ 44.8200'' W |
|---|---|
| Latitude | 37.99742 |
| Longitude | -121.71245 |
| Altitude | 5 m |
| Country | United States |