Distance from Portoviejo to Prospect Heights
Distance from Portoviejo to Prospect Heights is 4,838 kilometers. This air travel distance is equal to 3,006 miles.
The air travel (bird fly) shortest distance between Portoviejo and Prospect Heights is 4,838 km or 3,006 miles.
If you travel with an airplane (which has average speed of 560 miles) from Portoviejo to Prospect Heights, It takes 5.37 hours to arrive.
Portoviejo
Portoviejo is located in Ecuador.
| GPS Coordinates (DMS) | 1° 3´ 16.4880'' S 80° 27´ 16.0200'' W |
|---|---|
| Latitude | -1.05458 |
| Longitude | -80.45445 |
| Altitude | 44 m |
| Country | Ecuador |
Portoviejo Distances to Cities
| Portoviejo | Distance |
|---|---|
| Distance from Portoviejo to Prospect Heights | 4,838 km |
| Distance from Portoviejo to Bothell | 6,750 km |
| Distance from Portoviejo to Savage | 5,235 km |
| Distance from Portoviejo to Castro Valley | 6,056 km |
| Distance from Portoviejo to Pinole | 6,092 km |
Prospect Heights
Prospect Heights is located in United States.
| GPS Coordinates | 42° 5´ 43.0800'' N 87° 56´ 15.2520'' W |
|---|---|
| Latitude | 42.09530 |
| Longitude | -87.93757 |
| Altitude | 207 m |
| Country | United States |