Distance from Lodeynoye Pole to Springville
Distance from Lodeynoye Pole to Springville is 8,382 kilometers. This air travel distance is equal to 5,208 miles.
The air travel (bird fly) shortest distance between Lodeynoye Pole and Springville is 8,382 km or 5,208 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lodeynoye Pole to Springville, It takes 9.3 hours to arrive.
Lodeynoye Pole
Lodeynoye Pole is located in Russia.
| GPS Coordinates (DMS) | 60° 43´ 33.6000'' N 33° 33´ 11.0160'' E |
|---|---|
| Latitude | 60.72600 |
| Longitude | 33.55306 |
| Altitude | 21 m |
| Country | Russia |
Lodeynoye Pole Distances to Cities
| Lodeynoye Pole | Distance |
|---|---|
| Distance from Lodeynoye Pole to Omaha | 7,810 km |
| Distance from Lodeynoye Pole to Springville | 8,382 km |
| Distance from Lodeynoye Pole to Garfield Heights | 7,259 km |
| Distance from Lodeynoye Pole to Canyon Lake | 9,056 km |
| Distance from Lodeynoye Pole to Evansville | 7,834 km |
Springville
Springville is located in United States.
| GPS Coordinates | 40° 9´ 54.8280'' N 111° 36´ 38.7000'' W |
|---|---|
| Latitude | 40.16523 |
| Longitude | -111.61075 |
| Altitude | 1401 m |
| Country | United States |