Distance from Lodeynoye Pole to Evansville
Distance from Lodeynoye Pole to Evansville is 7,834 kilometers. This air travel distance is equal to 4,868 miles.
The air travel (bird fly) shortest distance between Lodeynoye Pole and Evansville is 7,834 km or 4,868 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lodeynoye Pole to Evansville, It takes 8.69 hours to arrive.
Lodeynoye Pole
Lodeynoye Pole is located in Russia.
| GPS Coordinates (DMS) | 60° 43´ 33.6000'' N 33° 33´ 11.0160'' E |
|---|---|
| Latitude | 60.72600 |
| Longitude | 33.55306 |
| Altitude | 21 m |
| Country | Russia |
Lodeynoye Pole Distances to Cities
| Lodeynoye Pole | Distance |
|---|---|
| Distance from Lodeynoye Pole to Omaha | 7,810 km |
| Distance from Lodeynoye Pole to Springville | 8,382 km |
| Distance from Lodeynoye Pole to Garfield Heights | 7,259 km |
| Distance from Lodeynoye Pole to Canyon Lake | 9,056 km |
| Distance from Lodeynoye Pole to Evansville | 7,834 km |
Evansville
Evansville is located in United States.
| GPS Coordinates | 37° 58´ 29.1360'' N 87° 33´ 21.0600'' W |
|---|---|
| Latitude | 37.97476 |
| Longitude | -87.55585 |
| Altitude | 118 m |
| Country | United States |