Distance from Laibin to Savage
Distance from Laibin to Savage is 12,083 kilometers. This air travel distance is equal to 7,508 miles.
The air travel (bird fly) shortest distance between Laibin and Savage is 12,083 km or 7,508 miles.
If you travel with an airplane (which has average speed of 560 miles) from Laibin to Savage, It takes 13.41 hours to arrive.
Laibin
Laibin is located in China.
| GPS Coordinates (DMS) | 23° 41´ 60.0000'' N 109° 16´ 0.0120'' E |
|---|---|
| Latitude | 23.70000 |
| Longitude | 109.26667 |
| Altitude | 83 m |
| Country | China |
Laibin Distances to Cities
| Laibin | Distance |
|---|---|
| Distance from Laibin to Holland | 12,477 km |
| Distance from Laibin to Hoboken | 12,862 km |
| Distance from Laibin to Cave Spring | 13,191 km |
| Distance from Laibin to Edgewater | 14,074 km |
| Distance from Laibin to Savage | 12,083 km |
Savage
Savage is located in United States.
| GPS Coordinates | 44° 46´ 44.8680'' N 93° 20´ 10.8240'' W |
|---|---|
| Latitude | 44.77913 |
| Longitude | -93.33634 |
| Altitude | 216 m |
| Country | United States |