Distance from Chocope to Fridley
Distance from Chocope to Fridley is 6,023 kilometers. This air travel distance is equal to 3,743 miles.
The air travel (bird fly) shortest distance between Chocope and Fridley is 6,023 km or 3,743 miles.
If you travel with an airplane (which has average speed of 560 miles) from Chocope to Fridley, It takes 6.68 hours to arrive.
Chocope
Chocope is located in Peru.
| GPS Coordinates (DMS) | 7° 47´ 29.0040'' S 79° 13´ 18.0120'' W |
|---|---|
| Latitude | -7.79139 |
| Longitude | -79.22167 |
| Altitude | 109 m |
| Country | Peru |
Chocope Distances to Cities
| Chocope | Distance |
|---|---|
| Distance from Chocope to Fridley | 6,023 km |
| Distance from Chocope to Dayton | 5,289 km |
| Distance from Chocope to Beltsville | 5,189 km |
| Distance from Chocope to Selden | 5,425 km |
| Distance from Chocope to Banning | 6,090 km |
Fridley
Fridley is located in United States.
| GPS Coordinates | 45° 5´ 9.8880'' N 93° 15´ 47.8080'' W |
|---|---|
| Latitude | 45.08608 |
| Longitude | -93.26328 |
| Altitude | 260 m |
| Country | United States |