Distance from Changsha to Sevastopol
Distance from Changsha to Sevastopol is 7,072 kilometers. This air travel distance is equal to 4,394 miles.
The air travel (bird fly) shortest distance between Changsha and Sevastopol is 7,072 km or 4,394 miles.
If you travel with an airplane (which has average speed of 560 miles) from Changsha to Sevastopol, It takes 7.85 hours to arrive.
Changsha
Changsha is located in China.
| GPS Coordinates (DMS) | 28° 11´ 55.4640'' N 112° 58´ 15.1320'' E |
|---|---|
| Latitude | 28.19874 |
| Longitude | 112.97087 |
| Altitude | 67 m |
| Country | China |
Changsha Distances to Cities
| Changsha | Distance |
|---|---|
| Distance from Changsha to Nizhyn | 7,023 km |
| Distance from Changsha to Sevastopol | 7,072 km |
Sevastopol
Sevastopol is located in Ukraine.
| GPS Coordinates | 44° 35´ 19.7880'' N 33° 31´ 20.6400'' E |
|---|---|
| Latitude | 44.58883 |
| Longitude | 33.52240 |
| Altitude | 72 m |
| Country | Ukraine |