Distance from Cedar Park to Rustenburg
Distance from Cedar Park to Rustenburg is 14,654 kilometers. This air travel distance is equal to 9,106 miles.
The air travel (bird fly) shortest distance between Cedar Park and Rustenburg is 14,654 km or 9,106 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cedar Park to Rustenburg, It takes 16.26 hours to arrive.
Cedar Park
Cedar Park is located in United States.
| GPS Coordinates (DMS) | 30° 30´ 18.7200'' N 97° 49´ 13.0440'' W |
|---|---|
| Latitude | 30.50520 |
| Longitude | -97.82029 |
| Altitude | 278 m |
| Country | United States |
Cedar Park Distances to Cities
| Cedar Park | Distance |
|---|---|
| Distance from Cedar Park to Johannesburg | 14,749 km |
| Distance from Cedar Park to Pretoria | 14,747 km |
| Distance from Cedar Park to Brits | 14,704 km |
| Distance from Cedar Park to Rustenburg | 14,654 km |
| Distance from Cedar Park to Port Elizabeth | 14,743 km |
Rustenburg
Rustenburg is located in South Africa.
| GPS Coordinates | 25° 40´ 3.2160'' S 27° 14´ 31.4880'' E |
|---|---|
| Latitude | -25.66756 |
| Longitude | 27.24208 |
| Altitude | 1171 m |
| Country | South Africa |