Distance from Cedar Park to Johannesburg
Distance from Cedar Park to Johannesburg is 14,749 kilometers. This air travel distance is equal to 9,165 miles.
The air travel (bird fly) shortest distance between Cedar Park and Johannesburg is 14,749 km or 9,165 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cedar Park to Johannesburg, It takes 16.37 hours to arrive.
Cedar Park
Cedar Park is located in United States.
| GPS Coordinates (DMS) | 30° 30´ 18.7200'' N 97° 49´ 13.0440'' W |
|---|---|
| Latitude | 30.50520 |
| Longitude | -97.82029 |
| Altitude | 278 m |
| Country | United States |
Cedar Park Distances to Cities
| Cedar Park | Distance |
|---|---|
| Distance from Cedar Park to Johannesburg | 14,749 km |
| Distance from Cedar Park to Pretoria | 14,747 km |
| Distance from Cedar Park to Brits | 14,704 km |
| Distance from Cedar Park to Rustenburg | 14,654 km |
| Distance from Cedar Park to Port Elizabeth | 14,743 km |
Johannesburg
Johannesburg is located in South Africa.
| GPS Coordinates | 26° 12´ 8.1720'' S 28° 2´ 37.0680'' E |
|---|---|
| Latitude | -26.20227 |
| Longitude | 28.04363 |
| Altitude | 1767 m |
| Country | South Africa |