Distance from Bhubaneshwar to Huntington Park
Distance from Bhubaneshwar to Huntington Park is 13,485 kilometers. This air travel distance is equal to 8,379 miles.
The air travel (bird fly) shortest distance between Bhubaneshwar and Huntington Park is 13,485 km or 8,379 miles.
If you travel with an airplane (which has average speed of 560 miles) from Bhubaneshwar to Huntington Park, It takes 14.96 hours to arrive.
Bhubaneshwar
Bhubaneshwar is located in India.
| GPS Coordinates (DMS) | 20° 16´ 20.6760'' N 85° 50´ 1.8600'' E |
|---|---|
| Latitude | 20.27241 |
| Longitude | 85.83385 |
| Altitude | 62 m |
| Country | India |
Bhubaneshwar Distances to Cities
| Bhubaneshwar | Distance |
|---|---|
| Distance from Bhubaneshwar to Clearwater | 14,530 km |
| Distance from Bhubaneshwar to Kaysville | 12,974 km |
| Distance from Bhubaneshwar to Huntington Park | 13,485 km |
| Distance from Bhubaneshwar to Mount Clemens | 12,948 km |
| Distance from Bhubaneshwar to Berea | 13,064 km |
Huntington Park
Huntington Park is located in United States.
| GPS Coordinates | 33° 58´ 54.0480'' N 118° 13´ 30.2520'' W |
|---|---|
| Latitude | 33.98168 |
| Longitude | -118.22507 |
| Altitude | 55 m |
| Country | United States |