Distance from Banmankhi to Severn
Distance from Banmankhi to Severn is 12,615 kilometers. This air travel distance is equal to 7,839 miles.
The air travel (bird fly) shortest distance between Banmankhi and Severn is 12,615 km or 7,839 miles.
If you travel with an airplane (which has average speed of 560 miles) from Banmankhi to Severn, It takes 14 hours to arrive.
Banmankhi
Banmankhi is located in India.
| GPS Coordinates (DMS) | 25° 53´ 12.0120'' N 87° 11´ 41.6760'' E |
|---|---|
| Latitude | 25.88667 |
| Longitude | 87.19491 |
| Altitude | 48 m |
| Country | India |
Banmankhi Distances to Cities
| Banmankhi | Distance |
|---|---|
| Distance from Banmankhi to Muscatine | 12,550 km |
| Distance from Banmankhi to Ocala | 13,805 km |
| Distance from Banmankhi to Kernersville | 13,013 km |
| Distance from Banmankhi to Chicago | 12,486 km |
| Distance from Banmankhi to Severn | 12,615 km |
Severn
Severn is located in United States.
| GPS Coordinates | 39° 8´ 13.3800'' N 76° 41´ 53.8800'' W |
|---|---|
| Latitude | 39.13705 |
| Longitude | -76.69830 |
| Altitude | 49 m |
| Country | United States |