Distance from Asyut to Jeffersonville
Distance from Asyūţ to Jeffersonville is 10,239 kilometers. This air travel distance is equal to 6,362 miles.
The air travel (bird fly) shortest distance between Asyūţ and Jeffersonville is 10,239 km= 6,362 miles.
If you travel with an airplane (which has average speed of 560 miles) from Asyut to Jeffersonville, It takes 11.36 hours to arrive.
Asyut
Asyut is located in Egypt.
| GPS Coordinates (DMS) | 27° 10´ 41.9160'' N 31° 11´ 9.3480'' E |
|---|---|
| Latitude | 27.17831 |
| Longitude | 31.18593 |
| Altitude | 61 m |
| Country | Egypt |
Asyūţ Distances to Cities
| Asyūţ | Distance |
|---|---|
| Distance from Asyut to Pinewood | 10,618 km |
| Distance from Asyut to Urbandale | 10,519 km |
| Distance from Asyut to Norco | 12,484 km |
| Distance from Asyut to Jeffersonville | 10,239 km |
| Distance from Asyut to Findlay | 9,912 km |
Jeffersonville
Jeffersonville is located in United States.
| GPS Coordinates | 38° 16´ 39.2520'' N 85° 44´ 13.8480'' W |
|---|---|
| Latitude | 38.27757 |
| Longitude | -85.73718 |
| Altitude | 138 m |
| Country | United States |