Distance from Aracaju to Charlottesville
Distance from Aracaju to Charlottesville is 6,922 kilometers. This air travel distance is equal to 4,301 miles.
The air travel (bird fly) shortest distance between Aracaju and Charlottesville is 6,922 km or 4,301 miles.
If you travel with an airplane (which has average speed of 560 miles) from Aracaju to Charlottesville, It takes 7.68 hours to arrive.
Aracaju
Aracaju is located in Brazil.
| GPS Coordinates (DMS) | 10° 54´ 39.9960'' S 37° 4´ 18.0120'' W |
|---|---|
| Latitude | -10.91111 |
| Longitude | -37.07167 |
| Altitude | 11 m |
| Country | Brazil |
Aracaju Distances to Cities
| Aracaju | Distance |
|---|---|
| Distance from Aracaju to San Ramon | 10,305 km |
| Distance from Aracaju to Charlottesville | 6,922 km |
| Distance from Aracaju to Somerville | 6,846 km |
| Distance from Aracaju to Havelock | 6,581 km |
| Distance from Aracaju to Coeur D Alene | 10,140 km |
Charlottesville
Charlottesville is located in United States.
| GPS Coordinates | 38° 1´ 45.5160'' N 78° 28´ 36.0480'' W |
|---|---|
| Latitude | 38.02931 |
| Longitude | -78.47668 |
| Altitude | 141 m |
| Country | United States |