Distance from Al `Amarah to Waterbury
Distance from Al ‘Amārah to Waterbury is 9,836 kilometers. This air travel distance is equal to 6,112 miles.
The air travel (bird fly) shortest distance between Al ‘Amārah and Waterbury is 9,836 km or 6,112 miles.
If you travel with an airplane (which has average speed of 560 miles) from Al `Amarah to Waterbury, It takes 10.91 hours to arrive.
Al `Amarah
Al `Amarah is located in Iraq.
| GPS Coordinates (DMS) | 31° 50´ 9.1680'' N 47° 8´ 38.3640'' E |
|---|---|
| Latitude | 31.83588 |
| Longitude | 47.14399 |
| Altitude | 9 m |
| Country | Iraq |
Al ‘Amārah Distances to Cities
| Al ‘Amārah | Distance |
|---|---|
| Distance from Al Amarah to Edmond | 11,675 km |
| Distance from Al Amarah to Flint | 10,325 km |
| Distance from Al Amarah to Fairview Heights | 11,039 km |
| Distance from Al Amarah to Sun City West | 12,444 km |
| Distance from Al Amarah to Waterbury | 9,836 km |
Waterbury
Waterbury is located in United States.
| GPS Coordinates | 41° 33´ 29.3400'' N 73° 3´ 5.4000'' W |
|---|---|
| Latitude | 41.55815 |
| Longitude | -73.05150 |
| Altitude | 84 m |
| Country | United States |