Distance from Aguazul to Barstow Heights
Distance from Aguazul to Barstow Heights is 5,628 kilometers. This air travel distance is equal to 3,497 miles.
The air travel (bird fly) shortest distance between Aguazul and Barstow Heights is 5,628 km or 3,497 miles.
If you travel with an airplane (which has average speed of 560 miles) from Aguazul to Barstow Heights, It takes 6.24 hours to arrive.
Aguazul
Aguazul is located in Colombia.
| GPS Coordinates (DMS) | 5° 10´ 22.1520'' N 72° 32´ 49.4160'' W |
|---|---|
| Latitude | 5.17282 |
| Longitude | -72.54706 |
| Altitude | 276 m |
| Country | Colombia |
Aguazul Distances to Cities
| Aguazul | Distance |
|---|---|
| Distance from Aguazul to Lisle | 4,341 km |
| Distance from Aguazul to Oshkosh | 4,581 km |
| Distance from Aguazul to Barstow Heights | 5,628 km |
| Distance from Aguazul to Douglas | 4,826 km |
| Distance from Aguazul to South Boston | 4,119 km |
Barstow Heights
Barstow Heights is located in United States.
| GPS Coordinates | 34° 52´ 10.9560'' N 117° 3´ 22.1400'' W |
|---|---|
| Latitude | 34.86971 |
| Longitude | -117.05615 |
| Altitude | 780 m |
| Country | United States |