Distance from Yakutsk to Faribault
Distance from Yakutsk to Faribault is 7,607 kilometers. This air travel distance is equal to 4,727 miles.
The air travel (bird fly) shortest distance between Yakutsk and Faribault is 7,607 km or 4,727 miles.
If you travel with an airplane (which has average speed of 560 miles) from Yakutsk to Faribault, It takes 8.44 hours to arrive.
Yakutsk
Yakutsk is located in Russia.
| GPS Coordinates (DMS) | 62° 2´ 2.0040'' N 129° 43´ 59.0160'' E |
|---|---|
| Latitude | 62.03389 |
| Longitude | 129.73306 |
| Altitude | 126 m |
| Country | Russia |
Yakutsk Distances to Cities
| Yakutsk | Distance |
|---|---|
| Distance from Yakutsk to Alliance | 8,261 km |
| Distance from Yakutsk to Torrington | 8,312 km |
| Distance from Yakutsk to Faribault | 7,607 km |
| Distance from Yakutsk to Tempe | 8,082 km |
| Distance from Yakutsk to San Benito | 9,363 km |
Faribault
Faribault is located in United States.
| GPS Coordinates | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |