Distance from Villeneuve-Saint-Georges to Oklahoma City
Distance from Villeneuve-Saint-Georges to Oklahoma City is 7,795 kilometers. This air travel distance is equal to 4,844 miles.
The air travel (bird fly) shortest distance between Villeneuve-Saint-Georges and Oklahoma City is 7,795 km= 4,844 miles.
If you travel with an airplane (which has average speed of 560 miles) from Villeneuve-Saint-Georges to Oklahoma City, It takes 8.65 hours to arrive.
Villeneuve-Saint-Georges
Villeneuve-Saint-Georges is located in France.
| GPS Coordinates (DMS) | 48° 43´ 55.8840'' N 2° 26´ 57.3000'' E |
|---|---|
| Latitude | 48.73219 |
| Longitude | 2.44925 |
| Altitude | 35 m |
| Country | France |
Villeneuve-Saint-Georges Distances to Cities
| Villeneuve-Saint-Georges | Distance |
|---|---|
| Distance from Villeneuve Saint Georges to Oklahoma City | 7,795 km |
| Distance from Villeneuve Saint Georges to Allen Park | 6,373 km |
| Distance from Villeneuve Saint Georges to Mint Hill | 6,704 km |
| Distance from Villeneuve Saint Georges to Waltham | 5,569 km |
| Distance from Villeneuve Saint Georges to Bettendorf | 6,889 km |
Oklahoma City
Oklahoma City is located in United States.
| GPS Coordinates | 35° 28´ 3.2160'' N 97° 30´ 59.1480'' W |
|---|---|
| Latitude | 35.46756 |
| Longitude | -97.51643 |
| Altitude | 395 m |
| Country | United States |