Distance from Veruela to Sevastopol
Distance from Veruela to Sevastopol is 9,578 kilometers. This air travel distance is equal to 5,951 miles.
The air travel (bird fly) shortest distance between Veruela and Sevastopol is 9,578 km or 5,951 miles.
If you travel with an airplane (which has average speed of 560 miles) from Veruela to Sevastopol, It takes 10.63 hours to arrive.
Veruela
Veruela is located in Philippines.
| GPS Coordinates (DMS) | 8° 4´ 23.1600'' N 125° 57´ 20.8800'' E |
|---|---|
| Latitude | 8.07310 |
| Longitude | 125.95580 |
| Altitude | 31 m |
| Country | Philippines |
Veruela Distances to Cities
| Veruela | Distance |
|---|---|
| Distance from Veruela to Smila | 9,629 km |
| Distance from Veruela to Yuzhne | 9,732 km |
| Distance from Veruela to Luts K | 10,057 km |
| Distance from Veruela to Sevastopol | 9,578 km |
Sevastopol
Sevastopol is located in Ukraine.
| GPS Coordinates | 44° 35´ 19.7880'' N 33° 31´ 20.6400'' E |
|---|---|
| Latitude | 44.58883 |
| Longitude | 33.52240 |
| Altitude | 72 m |
| Country | Ukraine |