Distance from Sverdlovs'k to San Angelo
Distance from Sverdlovs’k to San Angelo is 10,340 kilometers. This air travel distance is equal to 6,425 miles.
The air travel (bird fly) shortest distance between Sverdlovs’k and San Angelo is 10,340 km or 6,425 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sverdlovs'k to San Angelo, It takes 11.47 hours to arrive.
Sverdlovs'k
Sverdlovs'k is located in Ukraine.
| GPS Coordinates (DMS) | 48° 5´ 22.7040'' N 39° 39´ 8.7480'' E |
|---|---|
| Latitude | 48.08964 |
| Longitude | 39.65243 |
| Altitude | 271 m |
| Country | Ukraine |
Sverdlovs’k Distances to Cities
| Sverdlovs’k | Distance |
|---|---|
| Distance from Sverdlovs K to Cerritos | 10,661 km |
| Distance from Sverdlovs K to Normal | 8,966 km |
| Distance from Sverdlovs K to North Arlington | 8,207 km |
| Distance from Sverdlovs K to Lorain | 8,561 km |
| Distance from Sverdlovs K to Santa Ana | 10,669 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |