Distance from Slantsy to Lompoc
Distance from Slantsy to Lompoc is 9,215 kilometers. This air travel distance is equal to 5,726 miles.
The air travel (bird fly) shortest distance between Slantsy and Lompoc is 9,215 km or 5,726 miles.
If you travel with an airplane (which has average speed of 560 miles) from Slantsy to Lompoc, It takes 10.22 hours to arrive.
Slantsy
Slantsy is located in Russia.
| GPS Coordinates (DMS) | 59° 7´ 5.4120'' N 28° 5´ 28.9320'' E |
|---|---|
| Latitude | 59.11817 |
| Longitude | 28.09137 |
| Altitude | 41 m |
| Country | Russia |
Slantsy Distances to Cities
| Slantsy | Distance |
|---|---|
| Distance from Slantsy to League City | 8,885 km |
| Distance from Slantsy to Jacksonville Beach | 8,183 km |
| Distance from Slantsy to Tysons Corner | 7,169 km |
| Distance from Slantsy to Cahokia | 7,785 km |
| Distance from Slantsy to Lompoc | 9,215 km |
Lompoc
Lompoc is located in United States.
| GPS Coordinates | 34° 38´ 20.9400'' N 120° 27´ 28.5840'' W |
|---|---|
| Latitude | 34.63915 |
| Longitude | -120.45794 |
| Altitude | 34 m |
| Country | United States |