Distance from Sibut to Pashkovskiy
Distance from Sibut to Pashkovskiy is 4,770 kilometers. This air travel distance is equal to 2,964 miles.
The air travel (bird fly) shortest distance between Sibut and Pashkovskiy is 4,770 km or 2,964 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sibut to Pashkovskiy, It takes 5.29 hours to arrive.
Sibut
Sibut is located in Central African Republic.
| GPS Coordinates (DMS) | 5° 43´ 4.8360'' N 19° 4´ 26.0040'' E |
|---|---|
| Latitude | 5.71801 |
| Longitude | 19.07389 |
| Altitude | 431 m |
| Country | Central African Republic |
Sibut Distances to Cities
| Sibut | Distance |
|---|---|
| Distance from Sibut to Pashkovskiy | 4,770 km |
| Distance from Sibut to Nakhodka | 11,476 km |
| Distance from Sibut to Slantsy | 5,974 km |
| Distance from Sibut to Atkarsk | 5,646 km |
| Distance from Sibut to Salavat | 6,250 km |
Pashkovskiy
Pashkovskiy is located in Russia.
| GPS Coordinates | 45° 1´ 25.1760'' N 39° 6´ 15.6960'' E |
|---|---|
| Latitude | 45.02366 |
| Longitude | 39.10436 |
| Altitude | 29 m |
| Country | Russia |