Distance from Shenandoah to Polokwane
Distance from Shenandoah to Polokwane is 14,150 kilometers. This air travel distance is equal to 8,792 miles.
The air travel (bird fly) shortest distance between Shenandoah and Polokwane is 14,150 km or 8,792 miles.
If you travel with an airplane (which has average speed of 560 miles) from Shenandoah to Polokwane, It takes 15.7 hours to arrive.
Shenandoah
Shenandoah is located in United States.
| GPS Coordinates (DMS) | 30° 24´ 4.6800'' N 91° 0´ 3.3840'' W |
|---|---|
| Latitude | 30.40130 |
| Longitude | -91.00094 |
| Altitude | 14 m |
| Country | United States |
Shenandoah Distances to Cities
| Shenandoah | Distance |
|---|---|
| Distance from Shenandoah to Senekal | 14,139 km |
| Distance from Shenandoah to Polokwane | 14,150 km |
| Distance from Shenandoah to Knysna | 13,904 km |
| Distance from Shenandoah to Parys | 14,073 km |
| Distance from Shenandoah to Tembisa | 14,112 km |
Polokwane
Polokwane is located in South Africa.
| GPS Coordinates | 23° 54´ 16.1640'' S 29° 28´ 7.8600'' E |
|---|---|
| Latitude | -23.90449 |
| Longitude | 29.46885 |
| Altitude | 1315 m |
| Country | South Africa |