Distance from Sevastopol to Cedar City
Distance from Sevastopol to Cedar City is 10,296 kilometers. This air travel distance is equal to 6,398 miles.
The air travel (bird fly) shortest distance between Sevastopol and Cedar City is 10,296 km or 6,398 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sevastopol to Cedar City, It takes 11.42 hours to arrive.
Sevastopol
Sevastopol is located in Ukraine.
| GPS Coordinates (DMS) | 44° 35´ 19.7880'' N 33° 31´ 20.6400'' E |
|---|---|
| Latitude | 44.58883 |
| Longitude | 33.52240 |
| Altitude | 72 m |
| Country | Ukraine |
Sevastopol Distances to Cities
| Sevastopol | Distance |
|---|---|
| Distance from Sevastopol to San Ramon | 10,556 km |
| Distance from Sevastopol to Wilmington Island | 9,251 km |
| Distance from Sevastopol to Gilbert | 10,690 km |
| Distance from Sevastopol to East Point | 9,318 km |
| Distance from Sevastopol to Kirkwood | 9,219 km |
Cedar City
Cedar City is located in United States.
| GPS Coordinates | 37° 40´ 38.9280'' N 113° 3´ 42.8040'' W |
|---|---|
| Latitude | 37.67748 |
| Longitude | -113.06189 |
| Altitude | 1784 m |
| Country | United States |