Distance from Sawankhalok to Lake Havasu City
Distance from Sawankhalok to Lake Havasu City is 13,235 kilometers. This air travel distance is equal to 8,224 miles.
The air travel (bird fly) shortest distance between Sawankhalok and Lake Havasu City is 13,235 km= 8,224 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sawankhalok to Lake Havasu City, It takes 14.69 hours to arrive.
Sawankhalok
Sawankhalok is located in Thailand.
| GPS Coordinates (DMS) | 17° 18´ 57.4920'' N 99° 49´ 54.6960'' E |
|---|---|
| Latitude | 17.31597 |
| Longitude | 99.83186 |
| Altitude | 67 m |
| Country | Thailand |
Sawankhalok Distances to Cities
| Sawankhalok | Distance |
|---|---|
| Distance from Sawankhalok to Easley | 14,227 km |
| Distance from Sawankhalok to Drexel Hill | 13,645 km |
| Distance from Sawankhalok to Florin | 12,485 km |
| Distance from Sawankhalok to Gallup | 13,430 km |
| Distance from Sawankhalok to Lake Havasu City | 13,235 km |
Lake Havasu City
Lake Havasu City is located in United States.
| GPS Coordinates | 34° 29´ 2.0400'' N 114° 19´ 20.8200'' W |
|---|---|
| Latitude | 34.48390 |
| Longitude | -114.32245 |
| Altitude | 228 m |
| Country | United States |