Distance from San Giuseppe Vesuviano to Ladispoli
Distance from San Giuseppe Vesuviano to Ladispoli is 238 kilometers. This air travel distance is equal to 148 miles.
The air travel (bird fly) shortest distance between San Giuseppe Vesuviano and Ladispoli is 238 km or 148 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Giuseppe Vesuviano to Ladispoli, It takes 0.26 hours to arrive.
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
| GPS Coordinates (DMS) | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
|---|---|
| Latitude | 40.83034 |
| Longitude | 14.50342 |
| Altitude | 106 m |
| Country | Italy |
San Giuseppe Vesuviano Distances to Cities
Ladispoli
Ladispoli is located in Italy.
| GPS Coordinates | 41° 57´ 19.0800'' N 12° 4´ 44.3640'' E |
|---|---|
| Latitude | 41.95530 |
| Longitude | 12.07899 |
| Altitude | 13 m |
| Country | Italy |
Ladispoli Distances to Cities
| Ladispoli | Distance |
|---|---|
| Distance from Ladispoli to Florence | 214 km |
| Distance from Ladispoli to Anzio | 69 km |
| Distance from Ladispoli to Eboli | 291 km |
| Distance from Ladispoli to Fasano | 459 km |
| Distance from Ladispoli to Ciampino | 47 km |