Distance from San Cristobal to West Pokot
Distance from San Cristóbal to West Pokot is 11,583 kilometers. This air travel distance is equal to 7,197 miles.
The air travel (bird fly) shortest distance between San Cristóbal and West Pokot is 11,583 km or 7,197 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Cristobal to West Pokot, It takes 12.85 hours to arrive.
San Cristobal
San Cristobal is located in Dominican Republic.
| GPS Coordinates (DMS) | 18° 25´ 7.9680'' N 70° 6´ 11.0520'' W |
|---|---|
| Latitude | 18.41888 |
| Longitude | -70.10307 |
| Altitude | 34 m |
| Country | Dominican Republic |
San Cristóbal Distances to Cities
| San Cristóbal | Distance |
|---|---|
| Distance from San Cristobal to Uasin Gishu | 11,623 km |
| Distance from San Cristobal to Kiambu | 11,846 km |
| Distance from San Cristobal to West Pokot | 11,583 km |
| Distance from San Cristobal to Meru | 11,887 km |
West Pokot
West Pokot is located in Kenya.
| GPS Coordinates | 1° 35´ 32.7840'' N 35° 17´ 7.2960'' E |
|---|---|
| Latitude | 1.59244 |
| Longitude | 35.28536 |
| Altitude | 1906 m |
| Country | Kenya |