Distance from San Benito to Arlington Heights
Distance from San Benito to Arlington Heights is 1,978 kilometers. This air travel distance is equal to 1,229 miles.
The air travel (bird fly) shortest distance between San Benito and Arlington Heights is 1,978 km or 1,229 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Benito to Arlington Heights, It takes 2.19 hours to arrive.
San Benito
San Benito is located in United States.
| GPS Coordinates (DMS) | 26° 7´ 57.2880'' N 97° 37´ 51.9600'' W |
|---|---|
| Latitude | 26.13258 |
| Longitude | -97.63110 |
| Altitude | 16 m |
| Country | United States |
San Benito Distances to Cities
| San Benito | Distance |
|---|---|
| Distance from San Benito to Weslaco | 36 km |
| Distance from San Benito to Phoenix | 1,612 km |
| Distance from San Benito to Bellevue Wa | 3,210 km |
| Distance from San Benito to Bel Air North | 2,474 km |
| Distance from San Benito to Arlington Heights | 1,978 km |
Arlington Heights
Arlington Heights is located in United States.
| GPS Coordinates | 42° 5´ 18.0960'' N 87° 58´ 50.2680'' W |
|---|---|
| Latitude | 42.08836 |
| Longitude | -87.98063 |
| Altitude | 219 m |
| Country | United States |