Distance from San Antonio de la Cal to Asheboro
Distance from San Antonio de la Cal to Asheboro is 2,660 kilometers. This air travel distance is equal to 1,653 miles.
The air travel (bird fly) shortest distance between San Antonio de la Cal and Asheboro is 2,660 km or 1,653 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Antonio de la Cal to Asheboro, It takes 2.95 hours to arrive.
San Antonio de la Cal
San Antonio de la Cal is located in Mexico.
| GPS Coordinates (DMS) | 17° 1´ 41.9880'' N 96° 42´ 2.0160'' W |
|---|---|
| Latitude | 17.02833 |
| Longitude | -96.70056 |
| Altitude | 1553 m |
| Country | Mexico |
San Antonio de la Cal Distances to Cities
| San Antonio de la Cal | Distance |
|---|---|
| Distance from San Antonio De La Cal to Tyler | 1,703 km |
| Distance from San Antonio De La Cal to Solon | 3,070 km |
| Distance from San Antonio De La Cal to Holtsville | 3,479 km |
| Distance from San Antonio De La Cal to Prunedale | 3,288 km |
| Distance from San Antonio De La Cal to Asheboro | 2,660 km |
Asheboro
Asheboro is located in United States.
| GPS Coordinates | 35° 42´ 28.4760'' N 79° 48´ 49.1040'' W |
|---|---|
| Latitude | 35.70791 |
| Longitude | -79.81364 |
| Altitude | 256 m |
| Country | United States |