Distance from Sakhalin to Ridgewood
Distance from Sakhalin to Ridgewood is 9,229 kilometers. This air travel distance is equal to 5,735 miles.
The air travel (bird fly) shortest distance between Sakhalin and Ridgewood is 9,229 km or 5,735 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sakhalin to Ridgewood, It takes 10.24 hours to arrive.
Sakhalin
Sakhalin is located in Russia.
| GPS Coordinates (DMS) | 50° 41´ 27.5280'' N 142° 57´ 2.0520'' E |
|---|---|
| Latitude | 50.69098 |
| Longitude | 142.95057 |
| Altitude | 399 m |
| Country | Russia |
Sakhalin Distances to Cities
| Sakhalin | Distance |
|---|---|
| Distance from Sakhalin to Frisco | 9,030 km |
| Distance from Sakhalin to Cupertino | 7,229 km |
| Distance from Sakhalin to California | 7,433 km |
| Distance from Sakhalin to Ridgewood | 9,229 km |
| Distance from Sakhalin to Avocado Heights | 7,745 km |
Ridgewood
Ridgewood is located in United States.
| GPS Coordinates | 40° 58´ 45.3360'' N 74° 6´ 59.5080'' W |
|---|---|
| Latitude | 40.97926 |
| Longitude | -74.11653 |
| Altitude | 38 m |
| Country | United States |