Distance from to

Distance from Sakhalin to Ridgewood

Distance from Sakhalin to Ridgewood is 9,229 kilometers. This air travel distance is equal to 5,735 miles.

The air travel (bird fly) shortest distance between Sakhalin and Ridgewood is 9,229 km= 5,735 miles.

If you travel with an airplane (which has average speed of 560 miles) from Sakhalin to Ridgewood, It takes 10.24 hours to arrive.

Sakhalin

Sakhalin is located in Russia.

GPS Coordinates (DMS)50° 41´ 27.5280'' N
142° 57´ 2.0520'' E
Latitude50.69098
Longitude142.95057
Altitude399 m
CountryRussia

Map of Sakhalin

Sakhalin Distances to Cities

SakhalinDistance
Distance from Sakhalin to Frisco9,030 km
Distance from Sakhalin to Cupertino7,229 km
Distance from Sakhalin to California7,433 km
Distance from Sakhalin to Ridgewood9,229 km
Distance from Sakhalin to Avocado Heights7,745 km

Ridgewood

Ridgewood is located in United States.

GPS Coordinates40° 58´ 45.3360'' N
74° 6´ 59.5080'' W
Latitude40.97926
Longitude-74.11653
Altitude38 m
CountryUnited States

Map of Ridgewood