Distance from Polysayevo to Trussville
Distance from Polysayevo to Trussville is 10,206 kilometers. This air travel distance is equal to 6,342 miles.
The air travel (bird fly) shortest distance between Polysayevo and Trussville is 10,206 km or 6,342 miles.
If you travel with an airplane (which has average speed of 560 miles) from Polysayevo to Trussville, It takes 11.32 hours to arrive.
Polysayevo
Polysayevo is located in Russia.
| GPS Coordinates (DMS) | 54° 36´ 4.3200'' N 86° 14´ 45.2400'' E |
|---|---|
| Latitude | 54.60120 |
| Longitude | 86.24590 |
| Altitude | 217 m |
| Country | Russia |
Polysayevo Distances to Cities
| Polysayevo | Distance |
|---|---|
| Distance from Polysayevo to Aiken | 10,168 km |
| Distance from Polysayevo to Rockford | 9,260 km |
| Distance from Polysayevo to Rexburg | 8,964 km |
| Distance from Polysayevo to Trussville | 10,206 km |
| Distance from Polysayevo to Machesney Park | 9,252 km |
Trussville
Trussville is located in United States.
| GPS Coordinates | 33° 37´ 11.3880'' N 86° 36´ 31.9680'' W |
|---|---|
| Latitude | 33.61983 |
| Longitude | -86.60888 |
| Altitude | 212 m |
| Country | United States |